TicTacToe Game in python

by Anonymous 04:07:00 0 comments

def print_board(board):

print "The board look like this: \n"

for i in range(3):
print " ",
for j in range(3):
if board[i*3+j] == 1:
print 'X',
elif board[i*3+j] == 0:
print 'O',
elif board[i*3+j] != -1:
print board[i*3+j]-1,
else:
print ' ',

if j != 2:
print " | ",
print

if i != 2:
print "-----------------"
else:
print

def print_instruction():
print "Please use the following cell numbers to make your move"
print_board([2,3,4,5,6,7,8,9,10])


def get_input(turn):

valid = False
while not valid:
try:
user = raw_input("Where would you like to place " + turn + " (1-9)? ")
user = int(user)
if user >= 1 and user <= 9:
return user-1
else:
print "That is not a valid move! Please try again.\n"
print_instruction()
except Exception as e:
print user + " is not a valid move! Please try again.\n"

def check_win(board):
win_cond = ((1,2,3),(4,5,6),(7,8,9),(1,4,7),(2,5,8),(3,6,9),(1,5,9),(3,5,7))
for each in win_cond:
try:
if board[each[0]-1] == board[each[1]-1] and board[each[1]-1] == board[each[2]-1]:
return board[each[0]-1]
except:
pass
return -1

def quit_game(board,msg):
print_board(board)
print msg
quit()

def main():

# setup game
# alternate turns
# check if win or end
# quit and show the board

print_instruction()

board = []
for i in range(9):
board.append(-1)

win = False
move = 0
while not win:

# print board
print_board(board)
print "Turn number " + str(move+1)
if move % 2 == 0:
turn = 'X'
else:
turn = 'O'

# get user input
user = get_input(turn)
while board[user] != -1:
print "Invalid move! Cell already taken. Please try again.\n"
user = get_input(turn)
board[user] = 1 if turn == 'X' else 0

# advance move and check for end game
move += 1
if move > 4:
winner = check_win(board)
if winner != -1:
out = "The winner is "
out += "X" if winner == 1 else "O"
out += " :)"
quit_game(board,out)
elif move == 9:
quit_game(board,"No winner :(")

if __name__ == "__main__":
main()
raw_input()